Next, is completing the square. Here is how you complete the square: 1) Start with the original equation x^2+6x+2=0 Recall that y=ax^2+bx+c where a=1, b=6, and c=2.

You take the square root of both sides and make the right side have +- signs. Or you can write in standard form and factor. Given x^2 = 121 Take the square root of both sides (don't forget the +- on …

Jun 6, 2018 · How do you solve x2 − 5x = 0 by completing the square? Algebra Quadratic Equations and Functions Completing the Square

First, you must get each fraction over a common denominator which is x2 − 5x +6: x − 2 x − 2 x −2 x −3 + x − 3 x − 3 x − 3 x − 2 = 2x2 x2 − 5x + 6

x=5," extraneous solution " x=2 color (blue)"square both sides" (x-3)^2= (sqrt (x-1))^2 rArrx^2-6x+9=x-1 Equate the quadratic to zero rArrx^2-7x+10=0 Factorising the quadratic gives. (x-2) (x-5)=0 rArrx=5" …

Now, divide each side of the equation by #color (red) (9)# to solve for #x# while keeping the equation balanced:

See a solution process below: First, subtract color (red) (4x) and color (blue) (10) from each side of the equation to put this equation into standard form: x^2 - 9x - color (red) (4x) + 46 - color (blue) (10) = …

Jan 27, 2017 · First, multiply each side of the equation by 8(x − 2) to eliminate the fraction making the equation easier to work with and to keep the equation balanced: 8(x −2) × 17 8 = 8(x − 2) × 14 x − 2

Oct 16, 2017 · Explanation: Multiply both sides by #x# so you get rid of it as a denominator.

Subtract #9# from both sides and add #2sqrt (2x^2+x-10)# to both sides